I'm not sure why hints aren't working on the practice problems. Baffling.
If you're having trouble with any of them, I did work them all out this afternoon. Send me a message of some sort, and I will give you some hints of my own. Same goes for HW7 I suppose, if you're still having trouble.
If you're having trouble with any of them, I did work them all out this afternoon. Send me a message of some sort, and I will give you some hints of my own. Same goes for HW7 I suppose, if you're still having trouble.
Will you be in your office around 10 am?
ReplyDeleteProbably about 10:10, but yes.
ReplyDeletecan you please explain how we are supposed to enter the graph on HW 7 number 8. I know temperature is supposed to increase, level out, then increase again, but I cannot figure out how to enter it properly and I am losing points.
ReplyDeleteYou know the starting temperature and time, and the point at which temperature reaches zero, and you also know the time at which the temperature starts to rise again.
ReplyDeleteClick on the y axis for the starting point, then click on the x axis where temperature should be zero. click again at the time where it should start to rise again.
The last part is trickier - you have to calculate the temperature rise per minute when the water is liquid to get the slope right. You know that the heat put in is Q=(rate in J/min)(time in min). You also know that Q=cm(delta T). Comparing the two, you have
(delta T) = [(rate)/cm] * time
so the slope of the graph should be the rate divided by cm. From the slope, you know what the temperatures should be at (say) 10 minutes past the point at which the temperature begins to rise above zero.
Basically, it is like you think it should be, but the fact that it cares about the slope on the last part of the graph makes it trickier.
this does not work
ReplyDelete.....?
ReplyDeletenevermind, figured it out. thanks!
ReplyDelete